Answer:
The smallest ballon is the ballon X
Explanation:
It is possible to answer this question by using Graham's law:
[tex]\frac{v_1}{v_2} =\sqrt{\frac{MW_2}{MW_1}}[/tex]
Where v is the speed of effusion and MW is molar weight of each compound.
This equation is showing that speed is inversely related to the square root of its molar mass. As carbon dioxide has a bigger MW than carbon monoxide, the speed of effusion of carbon dioxide is lower doing its ballon biggest than carbon monoxide ballon, thus: The smallest ballon is the ballon X
I hope it helps!
