Respuesta :
Answer:
1.221g
Explanation:
First Sample
Ratio of Fe and Cl is given as;
Mass of Fe: Mass of Cl
1.302g : 2.483g
Second Sample;
Mass of Fe: Mass of Cl
xg : 2.329g
The ratio between both elements is constant in both samples, so we have;
Ratio of first sample = Ratio of second sample
1.302g : 2.483g = xg : 2.329g
1.302 / 2.483 = x / 2.329
x = (2.329 * 1.302) / 2.483
x = 1.221g
Answer:
Explanation:
Defining law of simple multiple proportions, which states that when two or more elements form more than one compound, the ratio of the weights of one element that combine with a given weight of another element in the different compounds is a ratio of small whole numbers
Ratio of Fe and Cl in the first sample is:
Mass of Fe: Mass of Cl
1.302 : 2.483
Ratio = 1 : 1.9
Therefore, in the other sample;
Mass of Fe: Mass of Cl
= 1 : 1.9
= x : 2.329
x = 2.329 ÷ 1.9
= 1.221 g.
