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As part of Lab 4 you will make and standardize a solution of NaOH(aq). Suppose in the lab you measure the solid NaOH and dissolve it into 100.0 mL of water. You then measure 0.2000 g of KHP (204.22 g/mol) and place it in a clean, dry 100-mL beaker, and then dissolve the KHP in about 25 mL of water and add a couple of drops of phenolphthalein indicator. You titrate this with your NaOH(aq) solution and find that the titration requires 9.78 mL of NaOH(aq). Part 1: How many moles of KHP are in your sample

Respuesta :

Answer: The moles of KHP in the sample is [tex]9.79\times 10^{-4}mol[/tex]

Explanation:

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Given mass of KHP = 0.2000 g

Molar mass of KHP = 204.22 g/mol

Putting values in above equation, we get:

[tex]\text{Moles of KHP}=\frac{0.2000g}{204.22g/mol}=9.793\times 10^{-4}mol[/tex]

Hence, the moles of KHP in the sample is [tex]9.79\times 10^{-4}mol[/tex]

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