. When iron rusts in air, iron(III) oxide is produced. How many moles of oxygen react with 2.4 mol of iron in the rusting reaction? 4Fe( s ) + 3O 2 ( g ) → 2Fe 2 O 3 ( s )

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Tringa0 Tringa0 · Answer 1 · 2020-03-03T10:42:36+01:00

Answer:

1.8 moles of oxygen react with 2.4 moles of iron in the rusting reaction.

Explanation:

[tex]4Fe(s) +3O_2 (g)\rightarrow 2Fe_2O_3(s)[/tex]

Moles of iron = 2.4 moles

According to reaction , 4 moles of iron reacts with 3 moles of oxygen gas.

Then 2.4 moles of iron will react with ;

[tex]2.4\times \frac{3}{4}=1.8 mol[/tex] of oxygen gas.

1.8 moles of oxygen react with 2.4 moles of iron in the rusting reaction.

virtuematane virtuematane · Answer 2 · 2022-01-13T12:48:27+01:00

1.8 moles of oxygen react with 2.4 moles of iron in the rusting reaction.

Give reaction:-

[tex]4Fe( s ) + 3O_2 ( g )\rightarrow 2Fe _2 O_ 3 ( s )[/tex]

Moles of iron = 2.4 moles

According to the reaction, 4 moles of iron reacts with 3 moles of oxygen gas.

Then 2.4 moles of iron will react with:-

[tex]2.4\ moles\ Fe\times\frac{3\ mol\ oxygen}{4moles\ Fe} =1.8\ mol\ oxygen[/tex]

So, 1.8 moles of oxygen react with 2.4 moles of iron in the rusting reaction.

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