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A chemist adds 290.0mL of a 1.02/molL calcium bromide CaBr2 solution to a reaction flask. Calculate the millimoles of calcium bromide the chemist has added to the flask. Round your answer to 3 significant digits.

Respuesta :

Answer : The millimoles of calcium bromide is, 296 mmol

Explanation : Given,

Volume of solution = 290.0 mL = 0.290 L

Concentration = 1.02 mol/L

Now we have to calculate the moles of calcium bromide.

[tex]\text{Moles of calcium bromide}=\text{Concentration}\times \text{Volume of solution}[/tex]

[tex]\text{Moles of calcium bromide}=1.02mol/L\times 0.290L[/tex]

[tex]\text{Moles of calcium bromide}=0.2958mol[/tex]

[tex]\text{Moles of calcium bromide}=295.8mmol\approx 296mmol[/tex]

Thus, the millimoles of calcium bromide is, 296 mmol

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