You throw a bouncy rubber ball and a wet lump of clay, both of mass m, at a wall. Both strike the wall at speed v, but while the ball bounces off with no loss of speed, the clay sticks. What is the change in momentum of the clay and ball, respectively?
O mv; 0
O mv; mv
O 0; mv
O 0, 2mv
O mv; 2 mv

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elcharly64 elcharly64 · Answer 1 · 2020-03-08T06:05:00+01:00

Answer:

The fifth option is the correct answer: mv; 2 mv

Explanation:

Change of Momentum

Assume an object has a momentum p1 and after some interaction it now has a momentum p2, the change of momentum is

[tex]\Delta p=p_2-p_1[/tex]

The momentum is computed as

[tex]p=mv[/tex]

Where m is the mass of the object and v its speed. Now let's analyze the situation of both the ball and the clay.

The clay has an initial speed v and a mass m, thus its initial momentum is

[tex]p_1=mv[/tex]

When it hits the wall, it sticks, thus its final speed is 0 and

[tex]p_2=0[/tex]

The change of momentum is

[tex]\Delta p=0-mv=-mv[/tex]

The absolute change is mv

Now for the ball, the initial condition is the same as it was for the clay, but the ball hits back at the same speed, thus its final momentum is

[tex]p_2=-mv[/tex]

The change of momentum is

[tex]\Delta p=-mv-mv=-2mv[/tex]

The absolute change is 2mv

The fifth option is the correct answer: mv; 2 mv