Answer:
a)
[tex]P(X = 0) = 0.64[/tex]
[tex]P(X = 1) = 0.11[/tex]
[tex]P(X = 2) = 0.25[/tex]
b) 0.75 = 75% probability that he makes no more than one of the shots
Step-by-step explanation:
We have these following probabilities:
64% = 0.64 probability that he misses both shots, that is, makes none of them.
11% = 0.11 probability that he makes one shot.
25% = 0.25 probability that he makes both shots.
a. Construct the appropriate probability distribution. (Round your answers to 2 decimal places.)
Binomial probability distribution, in which P(X = x) is the probability of making x shots. So
[tex]P(X = 0) = 0.64[/tex]
[tex]P(X = 1) = 0.11[/tex]
[tex]P(X = 2) = 0.25[/tex]
b. What is the probability that he makes no more than one of the shots? (Round your answer to 2 decimal places.)
[tex]P(X \leq 1) = P(X = 0) + P(X = 1) = 0.64 + 0.11 = 0.75[/tex]
0.75 = 75% probability that he makes no more than one of the shots
