Answer:
The molecular formula of the compound is [tex]C_6H_{12}O_6[/tex].
Explanation:
Let the molecular formula of the compound is [tex]C_xH_{y}O_z[/tex].in
Molar mass of compound = 180 g/mol
Number of carbon atom = x
Number of hydrogen atom = y
Number of oxygen atom = z
Atomic mass of carbon = 12 g/mol
Atomic mass of hydrogen = 1 g/mol
Atomic mass of oxygen = 16 g/mol
Percentage of element in compound :
[tex]=\frac{\text{number of atoms}\times \text{Atomic mass}}{\text{molar mas of compound}}\times 100[/tex]
Carbon :
[tex]40.00\%\%=\frac{x\times 12g/mol}{180 g/mol}\times 100[/tex]
x = 46
Hydrogen :
[tex]6.713\%=\frac{y\times 1 g/mol}{180 g/mol}\times 100[/tex]
y = 12
Oxygen:
[tex]53.28\%=\frac{z\times 16 g/mol}{180 g/mol}\times 100[/tex]
z = 5.99 ≈ 6
The molecular formula of the compound is [tex]C_6H_{12}O_6[/tex].
