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crate sits on a horizontal floor where the coefficient of static friction between the crate and the floor is 0.50. A 20-N force is applied to the crate acting to the right. What is the resulting static friction force acting on the crate

Respuesta :

Answer:

The resulting static friction force acting on the crate is 10 N.

Explanation:

Given that,

Coefficient of static friction = 0.50

Normal force = 20 N

We need to calculate the resulting static friction force acting on the crate

Using formula of static friction force

[tex]f_{s}=\mu_{s}N[/tex]

Where, N = normal force

[tex]\mu_{s}[/tex] = Coefficient of static friction

Put the value into the formula

[tex]f_{s}=0.50\times20[/tex]

[tex]f_{s}=10\ N[/tex]

Hence, The resulting static friction force acting on the crate is 10 N.

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