The final velocity is 5.87 m/s
Explanation:
Given-
mass, [tex]m_{1}[/tex] = 72 kg
speed, [tex]v_{1}[/tex] = 5.8 m/s
[tex]Mass_{2}[/tex],[tex]m_{2}[/tex] = 45 kg
[tex]speed_{2}[/tex],[tex]v_{2}[/tex] = 12 m/s
Θ = 60°
Final velocity, v = ?
Applying the conservation of momentum:
[tex]m_{1}[/tex] X [tex]v_{1}[/tex] + [tex]m_{2}[/tex] X [tex]v_{2}[/tex] = ([tex]m_{1}[/tex] +[tex]m_{2}[/tex] ) v
72 X 5.8 + 45 X 12 X cos 60° = (72 + 45) v
v = 417.6 + 540 X [tex]\frac{0.5}{117}[/tex]
v = 417.6 + [tex]\frac{270}{117}[/tex]
v = 5.87 m/s
The final velocity is 5.87 m/s
