Respuesta :
Answer:
The number of different choices the players have is 20,358,520.
Step-by-step explanation:
Combination can be used to solve this problem.
Combination is the selection of k objects from n distinct objects without replacement.
[tex]{n\choose k}=\frac{n!}{k!(n-k)!}[/tex]
The cards available are numbered from 1 to 52,i.e. there are total 52 cards.
A player has to select 6 cards from these 52 cards.
Compute the number of ways to select 6 cards from the 52 cards as follows:
[tex]{52\choose 6}=\frac{52!}{6!(52-6)!} =\frac{52!}{6!\times 46!} =\frac{52\times51\times50\times49\times48\times47\times46!}{6!\times46!}=20358520[/tex]
Thus, the number of different choices the players have is 20,358,520.
Answer: There are 20358520 ways to do so.
Step-by-step explanation:
Since we have given that
Numbers are written from 1 to 52
Numbers choose = 6
Since if repetition is not allowed.
We will use "combination":
Then the number of different ways to do so is given by
[tex]C(52,6)=^{52}C_6=20358520[/tex]
Hence, there are 20358520 ways to do so.
