Respuesta :
Explanation:
When work is done then there will occur change in volume. And, most change in volume occurs when there will be production of gas is taking place. We assume that no work is done when no gas is produced.
(a) For [tex]4Fe(s) + 3O_{2}(g) \rightarrow 2Fe_{2}O_{3}(s)[/tex]
Here, 3 moles of gas is producing 0 moles of gas. This means that work is done on the system.
(b) And, more is the production of a gas taking place in a reaction more will be the amount of work done by the system.
For [tex]2H_{2}O_{2}(g) \rightarrow O_{2}(g) + 2H_{2}O(g)[/tex]
Here, 2 moles of a gas is producing 3 moles of a gas. Since, gas is increasing so, work will be done by the system.
Whenever the volume changes, work is done. this volume fluctuates the most when there is gas production/reduction.
Suppose no work is done if no gas is created.
System work:
- The price of gasoline must rise.
[tex]2H_2O_2 \to O_2 + 2H_2O[/tex]
- 2 mol of [tex]H_2O_2[/tex] creates 3 mol of gases; gas increases
Work on the system:
- There is a gas decrease.
[tex]4Fe + 3O_2 \to 2F_2O_3[/tex]
- 3 mol of gas creates 0 mol of gas. there has been no work done. Gases do not alter.
Find out more information about the work:
brainly.com/question/14604434
