we have
[tex]f(x)=x^{2}-48[/tex]
To find the roots equate the function to zero
[tex]x^{2}-48=0[/tex]
Step 1
Adds [tex]48[/tex] to both sides of the equation
[tex]x^{2}-48+48=0+48[/tex]
[tex]x^{2}=48[/tex]
Step 2
Take the square root of both sides
[tex]\sqrt{x^{2}}= \sqrt{48}[/tex]
[tex]x=(+/-)\sqrt{48} \\x1=+\sqrt{48}=4\sqrt{3} \\ x2=-\sqrt{48}=-4\sqrt{3}[/tex]
therefore
the answer is
The roots are
[tex]x1=4\sqrt{3}[/tex]
[tex]x2=-4\sqrt{3}[/tex]
