Respuesta :
The question is incomplete, here is the complete question:
1. The radioactive source you will be working with in this lab is Cs-137. Look up the half-life of this material and report the value in units of seconds.
2. The relationship between decay constant (l) and half-life is:
[tex]t_{1/2}=\frac{\ln 2}{k}[/tex]
For Cs-137, what is the value of 'k' in [tex]s^{-1}[/tex]
Answer:
For 1: The half life for Cs-137 isotope is [tex]9.51\times 10^8s[/tex]
For 2: The rate constant of Cs-137 isotope is [tex]7.29\times 10^{-10}s^{-1}[/tex]
Explanation:
- For 1:
Half life is defined as the time taken for half of the reaction to complete. This is also defined as the time in which the concentration of a reactant is reduced to half of its original value.
The half life for Cs-137 isotope is [tex]9.51\times 10^8s[/tex]
- For 2:
The relationship between decay constant (l) and half-life is: given by the equation:
[tex]t_{1/2}=\frac{\ln 2}{k}[/tex]
where,
[tex]t_{1/2}[/tex] = half life of Cs-137 isotope = [tex]9.51\times 10^8s[/tex]
k = rate constant
Putting values in above equation, we get:
[tex]9.51\times 10^8s=\frac{\ln 2}{k}\\\\k=\frac{\ln 2}{9.51\times 10^8}=7.29\times 10^{-10}s^{-1}[/tex]
Hence, the rate constant of Cs-137 isotope is [tex]7.29\times 10^{-10}s^{-1}[/tex]
