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The perimeter of a rectangle is 15x + 17y
If the length is 7/2x + 7y then find the width of the rectangle.
Answer choices:
A. 4x + 3/2y
B. 8x + 3y
C. 8x + 10y
D. 4x + 3y

The perimeter of a rectangle is 15x 17y If the length is 72x 7y then find the width of the rectangle Answer choices A 4x 32y B 8x 3y C 8x 10y D 4x 3y class=

Respuesta :

Undeadtillidie

Answer: 8x+3y

Step-by-step explanation:

  • Set up an appropriate equation

You will need to subtract double the length by the perimiter since there are 2 sides of length

15x + 17y - (7/2x + 7y)2 =?

(15x + 17y) - (14/2x + 14y)=?

  • Simplify the Fraction to create whole numbers

(15x+17y) - (7x + 14y)

  • Combine like terms

Normally we would follow BPEMDAS but because there are not like terms in the parenthesis this is not necessary

  1. 15x - 7x = +8x
  2. 17y - 14y =+3y
  3. 8x+3y
  • Answer

8x+3y

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