If you wish to take a picture of a bullet traveling at 500 m/s, then a very brief flash of light produced by an RC discharge through a flash tube can limit blurring. Assuming 1.00 mm of motion during one RC constant is acceptable, and given that the flash is driven by a 600-μF capacitor, what is the resistance in the flash tube?

Respuesta :

Explanation:

The given data is as follows.

       Speed of the bullet (v) = 500 m/s

     Distance during one RC time constant (d) = 1 mm = [tex]1 \times 10^{-3} m[/tex]

      Capacitance (C) = 600 [tex]\mu F[/tex] = [tex]600 \times 10^{-6} F[/tex]

Hence, formula for speed of the bullet is as follows.

                v = [tex]\frac{d}{t}[/tex]

or,           t = [tex]\frac{d}{v}[/tex]

Time constant for RC circuit is as follows.

          t = RC

        R = [tex]\frac{t}{C}[/tex]

            = [tex]\frac{d}{vC}[/tex]

            = [tex]\frac{1 \times 10^{-3}}{500 \times 600 \times 10^{-6}}[/tex]

            = [tex]3.33 \times 10^{-3} ohm[/tex]

Thus, we can conclude that resistance in the flash tube is [tex]3.33 \times 10^{-3} ohm[/tex].