Explanation:
Relation between heat energy and specific heat is as follows.
[tex]q_{bomb} = c \times \Delta t[/tex]
or, c = [tex]\frac{q_{bomb}}{\Delta t}[/tex]
where, c = specific heat
[tex]q_{bomb}[/tex] = heat energy
[tex]\Delta t[/tex] = change in temperature
Putting the given values into the above formula we will calculate the specific heat as follows.
c = [tex]\frac{q_{bomb}}{\Delta t}[/tex]
= [tex]\frac{5.23 kJ}{7.33^{o}C}[/tex]
= 0.713 [tex]kJ^{o}C[/tex]
Thus, we can conclude that heat capacity C of the calorimeter is 0.713 [tex]kJ^{o}C[/tex].
The heat capacity C of the calorimeter is [tex]713.51J/^0C[/tex]
The formula for calculating the heat capacity is expressed as;
[tex]Q=mc \triangle t[/tex]
Q is the heat energy released
mc is the heat capacity
[tex]\triangle t[/tex] is the change in temperature
Given the following parameters
Q = 5230 Joules
[tex]\triangle t[/tex] = 7.33°C
Substitute the given parameters into the formula
[tex]Q=mc \triangle t\\mc=\frac{Q}{\triangle t} \\mc=\frac{5230}{7.33}\\mc= 713.51J/^0C[/tex]
Hence the heat capacity C of the calorimeter is [tex]713.51J/^0C[/tex]
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