Answer:
0.7 secs
Explanation:
In this question, the speed does not change as the mass changes. So we can use
Δt=Δ∨x/χgμ............................equ 1
To stop, the final speed will be 0
Therefore,
Δvx=vf-vt
Δvx=0-4m/s
= -4m/s
Now substitute the various values in equ 1
Δt=Δ∨x/χgμ
Δt= -4m/s/(9.8m/s∧2) (0.6)
Δt=0.7 secs
Answer:
Explanation:
The box stops at zero speed.
Final Velocity = 0 ,Initial speed (s)= -4 m/s
Therefore= change in velocity = Vf - Vi. ( 0 m/s- 4 m/s) = -4 m/s
Change in velocity = -0.4 m/s
Gravity g = 9.8 m/s^2
Mass= 0.8 g
-4 ms divided by 9.8 ms^2 * (0.8) = 0.51 s
It takes 0.51 seconds to stop
