Answer:
Gain in kinetic energy is [tex]1.6 \times 10^{-11} J[/tex]
or [tex]10^{8} eV[/tex]
Explanation:
The potential difference between the cloud and ground is 100 MV (million volts)
Charge on the electron q = [tex]1.6 \times 10^{-19} C[/tex]
Kinetic energy of an electron accelerated through this potential difference is the work done to move the electron.
hence kinetic energy gained is
[tex]KE= \Delta V \times q\\KE= 100 \times 10^6 \times 1.6 \times 10^{-19}\\KE=1.6 \times 10^{-11} J[/tex]
In terms of electron volts, the conversion factor is 1 electron volt (eV) =
[tex]1.6 \times 10^{-19} J[/tex]
So,
[tex]\frac{1.6 \times 10^{-11} J}{1.6 \times 10^{-19} J} \\= 10^8 eV[/tex]
