Answer:
324.6g
Explanation:
From this given problem, it is desirable to solve from the known specie to the unknown.
The balanced chemical combination is given as:
SrBr₂ + (NH₄)₂CO₃ → SrCO₃ + 2NH₄Br
Given;
2.1993 mole of (NH₄)₂CO₃ ;
Unknown:
Mass of SrCO₃ produced;
From the balanced equation, we see that;
1 mole of (NH₄)₂CO₃ reacted to produce 1 mole of SrCO₃
2.1993 mole of (NH₄)₂CO₃ will produce 2.1993 mole of SrCO₃
Mass of SrCO₃ produced = number of moles x molar mass of SrCO₃
Molar mass of SrCO₃ = 87.6 + 12 + 3(16) = 147.6g/mol
Mass of SrCO₃ = 2.1993 x 147.6 = 324.6g
