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4 Al + 3 O2 → 2 Al2O3

If 3.1581 moles of Al are reacted with 1.703 moles of O2, how many grams of Al2O3 will be produced?

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Answer:

322.1262g

Explanation:

This question is mole to mole reaction but the answer should be in gram.

4moles of Al gives 2 moles of Al2O3

3.1581 moles of Al gives x moles of Al2O3

Cross multiply

4x= 3.1581×2

4x=6.3162

X=6.3162/4

X=1.57905moles

To convert to gram

Moles ×molar mass

Molar mass of Al2O3 is 204g

Which means 1.57905×204= 322.1262g

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