Answer:
160.4K
Explanation:
Given parameters:
Initial volume of gas = 2.9L
Initial pressure of gas = 5atm
Initial temperature = 50°C
Final volume = 2.4L
Final pressure of gas= 3atm
Unknown:
Final temperature = ?
Solution:
To solve this problem, we have to apply the combined gas laws.
Mathematically, the law is expressed as;
[tex]\frac{P_{1}V_{1} }{T_{1} } = \frac{P_{2}V_{2} }{T_{2} }[/tex]
where P₁ is the initial pressure
V₁ is the initial volume
T₁ is the initial temperature
P₂ is the final pressure
V₂ is the final volume
T₂ is the final temperature
Since T₂ is the unknown, we must solve for it.
convert T₁ from °C to K;
T₁ = 273 + 50 = 323K
Now insert the parameters;
[tex]\frac{5 x 2.9}{323} = \frac{3 x 2.4}{T_{2} }[/tex]
[tex]T_{2}[/tex] = 160.4K
