Answer:
31.51 Hz.
Explanation:
Given,
length, L = 212 cm
density of string,[tex]\mu[/tex] = 0.02 g/cm
tension in the string = 357 N
Using Fundamental frequency equation
[tex]f = \dfrac{n}{2L}\sqrt{\dfrac{T}{\mu}}[/tex]
n=1
[tex]f = \dfrac{1}{2\times 2.12}\sqrt{\dfrac{357}{0.02}}[/tex]
[tex]f= 0.256\times 133.604[/tex]
[tex]f = 31.51\ Hz[/tex]
Therefore, fundamental frequency is equal to 31.51 Hz.
