Answer:
The ball travels at a speed of 11.662 m/s, making a 30.96° angle from the horizontal ground.
Explanation:
If the ball is thrown horizontally with a speed of 10.0 m/s and the hot air balloon is rising at a speed of 6.0 m/s then we can make the following deductions:
1. The ball is ALSO rising at a speed of 6.0 m/s
2. The vertical speed of the ball is 6.0 m/s
Thus the ball travels with 10 m/s horizontal and 6 m/s vertical speed relative to the ground.
To find the total speed and direction:
Total speed = [tex]\sqrt{(V_X)^2+(V_Y)^2}[/tex]
Total speed = [tex]\sqrt{10^2 + 6^2}[/tex]
Total speed = 11.662 m/s
Angle from the horizontal:
Tan( Angle ) = Perpendicular / Base
Tan (Angle) = Vertical Speed / Horizontal Speed
Tan (Angle) = 6/10
Angle = 30.96°
