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Aluminum has a density of 2.70 g/ cm3. What volume is occupied by a block of aluminum which weighs 4.32 kg?

Respuesta :

Answer:

1600cm3

Explanation:

From the question given, we obtained the following:

Density = 2.70g/cm3

Mass = 4.32kg :we need to convert the mass to grams

Mass = 4.32kg = 4.32 x 1000 = 4320g

Volume =?

Recall : Density = Mass /volume

Volume = Mass /Density

Volume = 4320/2.70

Volume = 1600cm3

The volume occupied by a block of aluminum which weighs 4.32 kg is 1600cm³.

DENSITY:

  • The density of a substance can be calculated by dividing the mass of the substance by its volume. This means that the volume can be calculated thus;

Volume = mass (g) ÷ density (g/cm³)

  • According to this question, a block of aluminum has a density of 2.70 g/cm³ and a mass of 4.32kg.

Mass in grams = 4.32 × 1000 = 4320g

Volume = 4320g ÷ 2.70g/cm³

Volume = 1600cm³

Therefore, the volume occupied by a block of aluminum which weighs 4.32 kg is 1600cm³.

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