Answer: The required percentage is 75% of print area filled with advertisement.
Step-by-step explanation:
Since we have given that
Part of the print area of the newspaper carried new = [tex]\dfrac{1}{4}[/tex]
Rest was filled with advertisements = [tex]1-\dfrac{1}{4}=\dfrac{4-1}{4}=\dfrac{3}{4}[/tex]
So, Percentage of the print area was filled with advertisement is given by
[tex]\dfrac{3}{4}\times 100\\\\=75\%[/tex]
Hence, the required percentage is 75% of print area filled with advertisement.
