contestada

Show that the curve y = 4 x 3 + 7 x − 5 y=4x3+7x-5 has no tangent line with slope 2 2. y = 4 x 3 + 7 x − 5 ⇒ m = y ' = y=4x3+7x-5⇒m=y′= Preview , but x 2 x2 0 0 for all x x, so m ≥ m≥ for all x x.

Respuesta :

xero099

Answer: The statement is true (see Step-by-step explanation).

Step-by-step explanation:

The slope of the tangent line for all point of the curve is determine by derive the expression abovementioned in the statement:

[tex]y' = 12 \cdot x^{2} + 7[/tex]

The previous expression represents a parabola, whose output will be positive for all [tex]x[/tex] due to the symmetry of [tex]x^{2}[/tex] and the positive coefficients of the polynomial. If the function is evaluated at [tex]x = 0[/tex], where the minimum occurs, it is evident that the smallest value is [tex]y' = 7[/tex] . Therefore, the inexistence of any tangent line with slope 2 associated with that curve is true.

Otras preguntas