Answer:
0.846×10²³
Explanation:
molar mass of aluminum is 26.9 g/mol.
converting the grams of aluminum to moles of aluminum.
mol Al = 3.78 g ×1 mol Al÷26.9 g = 0.1405 mol of Al
to determine the number of aluminum atoms present in 0.1405 mol Al we use the Avogrado's number which is equal to 6.022×10²³
Atoms of Al = 0.1405 mol Al×6.022×10²³
= 0.846×10²³
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