Acceleration of a speck is 0.77 m/s²
Explanation:
Given of the solution-
Diameter (We can represent as d) = 32 cm
radius, (We can represent as r )= 32/2 = 16 cm = 0.16 m
Angular acceleration,(We can represent as α ) = 46 rpm
[tex]\alpha = 46 * \frac{2\pi }{60}[/tex]
Acceleration, a = ?
We know that the formula for the acceleration is
[tex]a = r * \alpha[/tex]
[tex]a = 0.16 * 46 * \frac{2\pi }{60}\\ \\a = 0.16 * 46 * \frac{2 * 3.14}{60}[/tex]
[tex]a = 0.77m/s^2[/tex]
Therefore, acceleration of a speck is 0.77 m/s²
