Answer:
0.84 or 84%
Step-by-step explanation:
The probability of an apple tree being injured in this period, is the probability of it being injured by the first frost (0.6), added to the probability of it being injured by the second frost (0.6) minus the probability of it being injured by both frosts (0.6 x 0.6):
[tex]P = P(F_1)+P(F_2)-P(F_1\ and\ F_2)\\P=0.6+0.6-(0.6*0.6)\\P=0.84 = 84\%[/tex]
There is a 0.84 or 84% probability of an apple tree being injured in this period.
The value of probability can only be from 0 to 1. The probability of an apple tree being injured in this period is 0.84 or 84 %.
Probability means possibility. It deals with the occurrence of a random event. Its basic meaning is something is likely to happen. It is the ratio of the favorable event to the total number of events.
Frost damage to apple blossoms can severely reduce apple yield in commercial orchards.
It has been determined that the probability of a late spring frost causing blossom damage to Empire apple trees in the Hudson Valley of New York State is 0.6.
The probability of it being injured by first frost (0.6), added to the probability of it being injured second frost (0.6) minus the probability of it being injured by both touches of frost (0.6 × 0.6). That can be written as mathematically,
P = P(F₁) + P(F₂) - P(F₁ and F₂)
P = 0.6 + 0.6 - (0.6 × 0.6)
P 0.84
P = 84%
Thus, the probability of an apple tree being injured in this period is 0.84 or 84 %.
More about the probability link is given below.
https://brainly.com/question/795909
