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2' A mixture containing 2.75 gof ammonium chloride (NH4cl) in 5.0 g of water was heated to dissolve the solid and then allowed to cool in air. At 6f"C, the first crystals appeared in solution. What is the solubility of ammonium chloride (in g of NH4CIper 100 gof water) at 61 'C

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Answer:

55g NH₄Cl / 100g Water

Explanation:

Solubility of a substance define the amount of solute per solvent in a saturated solution. The solution can dissolve additional solute if heated.

In the problem, as the first crystal appears at 61°C the solubility in this temperature is the concentration of the solution, that is:

2,75g NH₄Cl / 5,0g water ₓ 100 = 55g NH₄Cl / 100g Water

I hope it helps!

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