Answer:
The ratio of electric field is 16:9.
Explanation:
Given that,
Radius [tex]R_{2}=\dfrac{3}{4}R_{1}[/tex]
Charge = Q
We know that,
The electric field is directly proportional to the charge and inversely proportional to the square of the distance.
In mathematically term,
[tex]E=\dfrac{kQ}{R^2}[/tex]
Here, [tex]E\propto\dfrac{1}{R^2}[/tex]
We need to calculate the ratio of electric field
Using formula of electric field
[tex]\dfrac{E_{2}}{E_{1}}=\dfrac{R_{1}^2}{R_{2}^2}[/tex]
Put the value into the formula
[tex]\dfrac{E_{2}}{E_{1}}=\dfrac{(4R_{1})^2}{(3R_{1})^2}[/tex]
[tex]\dfrac{E_{2}}{E_{1}}=\dfrac{16}{9}[/tex]
Hence, The ratio of electric field is 16:9.
