Respuesta :

marcthemathtutor

Answer:

-77, -78, -79

Step-by-step explanation:

let one of the integers be x

since the integers are consecutive, the other 2 integers must be

(x+1) and (x+2)

given that sum of the integers is -234,

x + (x+1) + (x+2) = -234

x + x + 1 + x + 2 = -234

3x + 3 = -234   (subtract 3 from both sides)

3x = -234-3

3x = -237  (divide both sides by 3)

x = -237 / 3

x = -79  (answer)

hence the other two numbers are

(x + 1) = -79 + 1 = -78 (answer)

and

(x+2) = -79 + 2 = -77 (answer)

usamaehmed

Answer:

Step-by-step explanation:

let the first integer is 'x', and by adding 1 in it we get the second integer that is 'x+1', and for third integer we need to add 1 in the previous integer i.e. is 'x+1' we get 'x+2'. Now all three integers we have are

x,x+1 and x+2.

since sum or add all three integer we get -234. so

x+x+1+x+2=-234

x+x+x=3x, and 1+2=3

3x+3=-234

3x=-234-3

3x=-237

x=-237/3

now the first integer is -237/3 or -79,

second integer is -78 and third integer is -77.

for verification add all three to get -234.

-79-78-77=-234. hence proved.

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