Answer:
[tex]\phi=6.28\times10^{-3}\;\;weber[/tex]
Explanation:
Given,
Magnetic field [tex]B=0.2\;\;T\\[/tex]
Radius [tex]r=0.1\;\;m[/tex]
The angle between the area vector and magnetic field is 0 degree, because the direction of area vector is always perpendicular to the plane.
[tex]\phi=BAcos\theta\\\phi=o.2\times\pi (0.1)^2\times cos0^o\\\phi=0.00628\;\;weber\\\phi=6.28\times10^{-3}\;\;weber[/tex]
