Really could use some help

In triangles △ABC and △DEF, m∠A=m∠E, m∠C=m∠F, AC=6, EF=2, and AB=3.3, side

DF

is shorter than side

BC

by 3.2. Find the unknown sides of these triangles.

Respuesta :

Answer:

BC=4.8

DE=1.1

DF=1.6

Step-by-step explanation:

Since sides of similar triangles are proportional, I used this to calculate DE

[tex] \frac{3.3}{de} = \frac{6}{2} [/tex]

Cross-multiply

[tex]3.3 \times 2 = 6 \times de[/tex]

[tex] \frac{6.6 = 6de}{6} [/tex]

[tex]1.1 = de[/tex]

To solve for BC and DF

[tex] \frac{6}{2} = \frac{bc}{bc - 2} [/tex]

BC-3.2=DE

Cross multiply

[tex]6bc - 19.2 = 2bc[/tex]

[tex]6bc - 2bc = 19.2[/tex]

as -19.2 is transferred to the opposite side od the equation, its value becomes opposite aswell (negative to positive)

[tex] \frac{4bc = 19.2}{4} [/tex]

Simplify and divide both by 4

[tex]bc = 4.8[/tex]

Since BC-3.2=DE, substitute BC with 4.8

[tex]4.8 - 3.2 = de[/tex]

[tex]de = 1.6[/tex]