Respuesta :
Answer: The mass of oxygen that will react with same amount of carbon as in carbon monoxide is 23.31 grams.
Explanation:
Law of multiple proportions states that when two elements combine to form two or more compounds in more than one proportion. The mass of one element that combine with a given mass of the other element are present in the ratios of small whole number. For Example: [tex]Cu_2O\text{ and }CuO[/tex]
We are given:
Mass of oxygen in CO = 13.6 grams
- For carbon monoxide (CO):
Applying unitary method:
16 grams of oxygen are reacting with 12 grams of carbon
So, 13.6 grams of oxygen will be reacting with = [tex]\frac{12}{16}\times 13.6=10.2g[/tex] of carbon
- For carbon dioxide [tex](CO_2)[/tex] :
Applying unitary method:
12 grams of carbon are reacting with 32 grams of oxygen
So, 10.2 grams of carbon will be reacting with = [tex]\frac{32}{12}\times 10.2=23.31g[/tex] of oxygen
Hence, the mass of oxygen that will react with same amount of carbon as in carbon monoxide is 23.31 grams.
In the given question, 27.2 grams of oxygen will react with 10.2 grams of carbon to give 39.1 grams of carbon dioxide.
Calculations based on the law of multiple proportions:
The mass of oxygen given in the question is 13.6 grams. The molecular mass of oxygen or O2 is 32 g/mol.
The reactions taking place in the given case are:
- 2C + O₂ ⇔ 2CO --------- (i)
- C + O₂ ⇔ CO₂ ---------- (ii)
Now the number of moles of O₂ will be,
[tex]Moles of O2= \frac{Weight}{Molecular mass}[/tex]
[tex]Moles = \frac{13.6}{32} \\Moles = 0.425 moles[/tex]
Based on the reaction, it can be seen that with 1 mole of O₂, 2 moles of C react to produce 2 moles of CO.
Now for 0.425 moles of oxygen,
The moles of C, that is, 0.425 × 2 = 0.850 moles will react 0.425 moles of O₂ to produce 0.850 moles of CO
Now the number of moles of C is 0.850 moles, and the molecular mass of C is 12 g/mol.
The mass of C will be,
Mass = Number of moles × Molecular mass
Mass = 0.850 × 12 = 10.2 grams
Now in the second reaction, that is, in the formation of CO₂, 1 mole of C will react with 1 mole of O₂ to produce 1 mole of CO₂.
Therefore, 0.850 moles of C will react with 0.850 moles of O₂ to give 0.850 moles of CO₂.
Now the molar mass of CO₂ is 46 g/mol, the mass of CO₂ will be,
Mass = 0.850 moles × 46 = 39.1 grams
The moles of O₂ is 0.850 moles, the molar mass of O₂ is 32 g/mol. Now the mass of O₂ is,
Mass = Number of moles × Molar mass
Mass = 0.850 × 32 g/mol
Mass = 27.2 grams
Thus, 27.2 grams of oxygen will react with 10.2 grams of carbon to produce 39.1 grams of CO₂.
Find out more information about calculations based on the law of multiple proportions here:
https://brainly.com/question/5190147
