Here given the linear equations of two variables
Now solve for x
[tex]\sf 5x+\dfrac{3}{2}= 6-\dfrac{2}{3}x[/tex]
Solution :-
Taking LCM :-
[tex]:\implies\sf \dfrac{10x+3}{2}= \dfrac{18-2x}{3}\\ \\ \\ :\implies\sf \ cross\ multiplication\\ \\ \\ :\implies\sf 3(10x+3)= 2(18-2x)\\ \\ \\ :\implies\sf 30x+9= 36 -4x\\ \\ \\ :\implies\sf 30x+4x= 36-9\\ \\ \\ :\implies\sf 34x= 27\\ \\ \\ :\implies\sf x= \dfrac{27}{34}[/tex]
[tex]\boxed{\bigstar{\sf\ value \ of x= \dfrac{27}{34}}}[/tex]
[tex]\underline{\therefore{\textit {\textbf{Option\ A \ is \ the \ correct \ answer}}}}[/tex]
