Answer:
Mean=3.5
Median=3.5
Range=6
Interquartile=1
Step-by-step explanation:
Given set of data is 0, 2, 3, 3, 3, 3, 3, 4, 4, 4, 4, 5, 5, 6
To find Mean , Median , Range and Interquartile range :
First finding Mean
- [tex]Mean=\frac{sum of the observations}{number of observations}[/tex]
- [tex]=\frac{0+2+3+3+3+3+3+4+4+4+4+5+5+6}{14}[/tex]
- [tex]=\frac{49}{14}[/tex]
- [tex]=\frac{7}{2}[/tex]
- [tex]=3.5[/tex]
Therefore Mean=3.5
Median:
- Since the number of observations is even, so the meadian becomes
- [tex]Median=\frac{sum of the two mid terms}{2}[/tex]
- [tex]=\frac{3+4}{2}[/tex]
- [tex]=\frac{7}{2}[/tex]
- [tex]=3.5[/tex]
Therefore Median=3.5
Range:
- Range=greatest value-least value
- In the given observations we have greatest value is 6 and least value is 0
- Therefore Range=6-0
Therefore Range=6
Interquartile:
- From the observations we have [tex]Q_1=3[/tex] and [tex]Q_3=4[/tex]
- [tex]Interquartile=Q_3-Q_1[/tex]
- [tex]=4-3[/tex]
Therefore Interquartile=1
