Respuesta :
Answer:
For this case we can define the following two events A and B.
In order to classify A and B as independent we needd to satisfy this condition:
[tex] P(A \cap B) = P(A) *P(B)[/tex]
None of the above.
True, because none of the options were correct.
See explanation below
Step-by-step explanation:
For this case we can define the following two events A and B.
In order to classify A and B as independent we need to satisfy this condition:
[tex] P(A \cap B) = P(A) *P(B)[/tex]
So let's analyze one by one the possible options:
the sum of their probabilities must be equal to one.
False, the sum of the probabilities can be <1 so this statement is not true
they must be mutually exclusive.
False when we talk about mutually exclusive events we are saying that:
[tex] P(A \cap B) =0[/tex]
But independence not always means that we have mutually exclusive events
their intersection must be zero.
False the intersection of the probabilities is 0 just if we have mutually exclusive events, not independent events
None of the above.
True, because none of the options were correct.
