SPANISH
Como el peso específico del objeto es Y = 9016 N / m ^ 3, puede ver que será Y = 300 N / V m ^ 3
V (m ^ 3) = 300 N / (9016 N / m ^ 3)
V (m ^ 3) = 0, =. 033 m ^ 3
1 Litro es 0,001 m ^ 3
(.033 m ^ 3) * (1 L / 0,001 m ^ 3) = 35,937 L
ENGLISH
Since the specific weight of the object is Y = 9016 N/ m^3 you can see that it will be Y = 300 N / V m^3
V(m^3) = 300 N / (9016 N/m^3)
V(m^3) = 0,=.033 m^3
1 Litro es 0,001 m^3
(.033 m^3) * (1 L / 0,001 m^3) = 35,937 L
Espero que esto ayude, ahora sabes la respuesta y cómo hacerlo. ¡QUE TENGAS UN DÍA BENDITO Y MARAVILLOSO! :-)
- Cutiepatutie ☺❀❤
The specific weight is the weight of the per unit volume of a material. The volume of the olive oil is 34 L.
The specific weight is the weight of the per unit volume of a material. It is given by the formula,
[tex]\rm Specific\ Weight, \gamma= Density \times g = \dfrac{Weight}{Volume}[/tex]
As the weight of the oil is given and the specific density is also given, therefore, we can find volume as,
[tex]\rm \gamma = \dfrac{Weight}{Volume}\\\\\rm 9016= \dfrac{300}{Volume}\\\\Volume = \dfrac{300}{9016}\\\\Volume = 0.0333\ m^3[/tex]
Now, we know that 1 m³ = 1000 litres, therefore,
[tex]\rm Volume = 0.034\ m^3\\\\Volume = (0.034 \times 1000)\ liters\\\\Volume = 34\ liters[/tex]
Hence, the volume of the olive oil is 34 L.
Learn more about Specific Weight:
https://brainly.com/question/13264782
