Answer:
Current (I) = 3 x 10^-2 A
Explanation:
As we know, [tex]B = 4\pi 10^-7 *l/ 2\pi r[/tex]
By putting up the values needed from the data...
Current (I) = 2 x 3.14 x (3.0 x 10^-6) (2.0 x 10^-3) / 4 x 3.14 x 10^-7 = 3 x 10^-2 A
Answer: 0.03002A
Explanation: The formulae that relates the magnetic field strength B at a point (r) away from the center of a conductor carrying a current of value (I) is given below as
B = Uo×I/2πr
From our question, B =2.0×10^-3 T, r = 3.0×10^-6m
I =?, Uo = permeability of free space = 1.256×10^-6 mkg/s²A².
By substituting the parameters, we have that
2×10^-3 = 1.256×10^-6 × I/2π(3.0×10^-6)
2×10^-3 × 2π(3.0×10^-6) = 1.256×10^-6 × I
3.77×10^-8 = 1.256×10^-6 × I
I = 3.77×10^-8/ 1.256×10^-6
I = 3.002×10^-2 = 0.03002A
