Answer:
[tex]1.5\times 10^{11}}[/tex]
Explanation:
We are given that
Electric field=[tex]E=3\times 10^6 N/C[/tex]
Dimension of parallel plate capacitor=[tex]3 cm\times 3 cm[/tex]
Area of parallel plate capacitor=[tex]A=3\times 3=9 cm^2=9\times 10^{-4}m^2[/tex]
[tex]1 cm^2=10^{-4} m^2[/tex]
We have to find the number of electrons must be transferred from one electrode to the other to create a spark between the electrodes.
[tex]E=\frac{Q}{\epsilon_0A}[/tex]
Where [tex]\epsilon_0=8.85\times 10^{-12}C^2/Nm^2[/tex]
Substitute the values
[tex]3\times 10^6=\frac{Q}{8.85\times 10^{-12}\times 9\times 10^{-4}}[/tex]
[tex]Q=3\times 10^6\times 8.85\times 10^{-12}\times 9\times 10^{-4}}[/tex]
[tex]Q=2.4\times 10^{-8} C[/tex]
We know that
[tex]Q=ne=n\times 1.6\times 10^{-19} [/tex]
Where e=[tex]1.6\times 10^{-19} C[/tex]
[tex]n=\frac{Q}{e}=\frac{2.4\times 10^{-8}}{1.6\times 10^{-19}}=1.5\times 10^{11}}[/tex]
