Two gene loci, A and B, assort independently, and alleles A and B are dominant over alleles a and b. Indicate the probability of producing an AB gamete from an AaBb individual.

Step 1. The two quality loci, A and B, assort autonomously.
The alleles A and B are predominant over the alleles an and b. In this way, when a cross happens between AaBb X AaBb, the subsequent gametes would be AB, Ab, aB, and ab.
Step 2.The offsprings which have in any event one A and B allele, will show AB phenotype.
Along these lines, AABB, AaBb, AABb, AaBB, will all have AB phenotype.

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Oseni Oseni · Answer 2 · 2021-10-22T23:56:16+02:00

If two gene loci, A and B, assort independently, the probability of producing an AB gamete from AaBb would be 1/4 or 25%

Since both A and B are independently inherited, Aa and Bb can be crossed just we would have it in a monohybrid cross following Mendelian pattern.

Thus:

Aa x Bb

AB Ab aB ab

The gametes and their respective probabilities of appearing would be:

AB - 1/4
Ab - 1/4
aB - 1/4
ab - 1/4

In other words, all 4 gametes have an equal chance of being produced during gametogenesis.

More on independent assortment of genes can be found here: https://brainly.com/question/13041062