Answer:
The answer is 181.437 ml of water to increase the soil's moisture content to 10%.
Explanation:
We have been given:
Soil weight = 5 lb = 2.26796 kg
2% of moisture ⇒ [tex]\frac{2}{100}[/tex] × 2.26796 = 0.045359 kg of water in the soil
10% of moisture ⇒ [tex]\frac{10}{100}[/tex] × 2.26796 = 0.226796 kg of water in the soil
The difference in moisture content = (0.226796 - 0.045359) kg
=0.181432 kg
But 1kg = 1000 ml
∴ 0.181437 kg = 181.437 ml of water required to increase the moisture content to 10%
