Answer:
188 s
Explanation:
We are told the reaction is second order respect to A so we know the expression for the rate law is
rate = - Δ[A]/Δt = k[A]²
where the symbol Δ stands for change, [A] is the concentration of A, and k is the rate constant.
The integrated rate law for this equation from calculus is
1 / [A]t = kt + 1/[A]₀
where [A]t is the concentration of A at time t, k is the rate constant, and [A]₀ is the initial concentration.
Since we have all the information required to solve this equation lets plug our values
1 / 0.280= 0.0130x t + 1 / 0.890
( 1 / 0.280 - 1 / 0.890)M⁻¹ = 0.0130 M⁻¹ ·s⁻¹t
t = 188 s
