Answer:
Final pressure of gas = 2 atm
Explanation:
Given data:
Initial pressure of gas = 1.50 atm
Initial temperature = 27°C
Final temperature = 127°C
Final pressure of gas = ?
Solution:
Initial temperature = 27°C (27+273 = 300 K)
Final temperature = 127°C ( 127+273 = 400 K)
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
1.50 atm / 300 K = P₂/400 K
P₂ = 1.50 atm × 400 K / 300 K
P₂ = 600 atm. K /300 K
P₂ = 2 atm
