Respuesta :

[tex] \red \mid \overline{answer}[/tex]

[tex]x {}^{2} + 12x + 35[/tex]

[tex]x {}^{2} + 7x + 5x + 35[/tex]

[tex]x(x + 7) + 5(x + 7)[/tex]

[tex](x + 5)(x + 7)[/tex]

Answer:

(x+5)(x+7)

Step-by-step explanation:

We need to find two binomials of the form (x+a) and (x+b) such that their product gives [tex]x^2+12x+35[/tex]

So, notice that  the values for "a" and for "b" in the binomials to factor should verify that :

1) a * b = 35

and 2) a+b = 12

Since the product (x+a) times (x+b) = [tex]x^2+ax+bx+a*b= x^2+(a+b)x +a*b[/tex]

The pair of values 7 and 5 satisfy such conditions.

Therefore (x+5) (x+7) = [tex]x^2+12x+35[/tex]

and then (x+5) and (x+7) are binomial factors of the original trinomial.