What is the volume of 4.5 mol of an ideal gas
at a pressure of 3 atm and a temperature of
0° C? 1 liter = 0.001 m and 1 atm = 101300
Pascals.
Answer in units of L.

Respuesta :

Answer:

33.6 L

Explanation:

We can solve the problem by using the equation of state for ideal gases, which states that:

[tex]pV=nRT[/tex]

where

p is the pressure of the gas

V is its volume

n is the number of moles

R is the gas constant

T is the absolute temperature of the gas

For the ideal gas in this problem we have:

n = 4.5 mol (number of moles)

p = 3 atm (pressure)

[tex]T=0^{\circ}C+273=273 K[/tex] is the temperature

[tex]R=0.082 Latm/mol K[/tex] is the gas constant

Solving for V, we find the volume of the gas:

[tex]V=\frac{nRT}{p}=\frac{(4.5)(0.082)(273)}{3}=33.6 L[/tex]