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Odyssey Quiz
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The velocity of a baseball is 25 m/s at an angle of 8° below the horizontal. If
a baseball has a mass of 0.15 kg, what is the horizontal component of its
momentum?
OA) 0.006 kg-m/s
OB) 0.2 kg-m/s
OC) 0.5 kg-m/s
OD 3.7 kg-m/s

Respuesta :

Answer:

OD) 3.7 kg-m/s

Explanation:

given:

velocity of baseball, v = 25 m/s

angle below horizontal, Θ = [tex]8^{o}[/tex]

mass of baseball, m = 0.15 kg

Generally, momentum (p) is given by equation:

p = mv

Horizontal component is given by

p = mv cosΘ

  = 0.15 kg x 25 m/s x cos [tex]8^{o}[/tex]

  = 3.71 kg- m/s

Hence horizontal component of momentum is OD) 3.7 kg-m/s

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