Answer:
The anvil will travel at the speed of 44.27 m/s
Explanation:
Given:
mass of anvil, m = 20 kg
height, h = 100 m
Here , work done is equal to change in kinetic energy. Here initial kinetic energy is zero. Hence work done is equal to final kinetic energy.
Work done = force * distance
= mg * h .............. (equation 1)
(here work done vertically is considered hence a= g = 9.8 m/[tex]s^{2}[/tex] and distance = h)
Also ,
work done = final kinetic energy
= [tex]\frac{1}{2}[/tex][tex]mv^{2}[/tex] ...............(equation 2)
from equation 1 and 2 , we get
mgh = [tex]\frac{1}{2}[/tex][tex]mv^{2}[/tex]
[tex]v^{2}[/tex] = 2gh
= 2 * 9.8 * 100
= 1960
v = 44.27 m/s
